13x^2-66x+5=0

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Solution for 13x^2-66x+5=0 equation:



13x^2-66x+5=0
a = 13; b = -66; c = +5;
Δ = b2-4ac
Δ = -662-4·13·5
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-64}{2*13}=\frac{2}{26} =1/13 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+64}{2*13}=\frac{130}{26} =5 $

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